-2x^2+15x-7=0

Solution for -2x^2+15x-7=0 equation:

-2x^2+15x-7=0

a = -2; b = 15; c = -7;
Δ = b2-4ac
Δ = 152-4·(-2)·(-7)
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-13}{2*-2}=\frac{-28}{-4}
=+7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+13}{2*-2}=\frac{-2}{-4}
=1/2
$